lim(x y)-(0,0) 2xy/x^2+y^4
Answers
Answered by
1
Step-by-step explanation:
Approach (0,0) along (t,t) as t→0 to get:
limt→0t3t2+t4=0
Approach (0,0) along (t,t√) as t→0 to get:
limt→0t2t2+t2=12
Thus, the limit doesn't exist.
Similar questions