Math, asked by madhumalathi817, 2 months ago

lim[x²+1]/x+100
x approach 1​

Answers

Answered by pranay9018
1

Answer:

Hope it Helps you

Step-by-step explanation:

\lim_{x \to 1} \frac{ {x}^{2}  + 1}{x} + 100 \\  =  >  \frac{ {1}^{2}  + 1}{1}  + 100 \\  =  >  \frac{2}{1}  + 100 \\  =  > 100 + 2 \\  =  > 102

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