Question

Lim (xcota-acotx)/(x-a)
x tends to a

Answer 1

Answer:

tq for giving me free points..

Answer 2

Answer:

Step-by-step explanation:

.Lim x tends to A = (xcotA-Acotx)/x-A

.Lim x tends to A= (xcotA-AcotA+AcotA-Acotx)/x-A

.Lim x tends to A=[(x-A).cotA+A(cotA-cotx)]/A-x

.Lim x tends to A=cotA + A/x-A (cosA/sinA - cosx/sinx)

.Lim x tends to A=cotA + A/x-A[(sinx.cosA-sinA.cosx)/sinA.sinx]

.Lim x tends to A=cotA + A/x-A . [sin(x-A)]/sinA.sinx

.cotA + Lim x tends to [sin(x-A)/x-A] . A/sinA.sinx

.cotA+1 . A/sin^2A

.cotA+A/sin^2 A