Question

limit 0 to infinity sinx/4x​

Answer 1

Answer:

WE KNOW THAT –

$lim_{x - > 0}( \frac{ \sin(x) }{x} ) = 1$

SO THAT –

$= \frac{1}{4} ( lim_{x - > 0}( \frac{ \sin(x) }{x} ) ) = \frac{1}{4}$

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Answer 2

ANSWER

PLEASE CORRECT YOUR QUESTION

HERE

WHERE X TENDING NOT GIVEN

IF YOU ASK O POWER INFINITY

THEN THESE PROBLEMS SOLVED BY TAKING LOG

IF IT IS

limx tends 0 sins/4x

then limit is 1/4 as limit xtends 0 sins/x =1

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