Question

Limit extends x=1 4x^2-1/2x-1

Answer 1

Answer:

Step-by-step explanation:

We have,

$\displaystyle\lim_{x\to1}\dfrac{4x^2-1}{2x-1}$

$\displaystyle=\lim_{x\to1}\dfrac{(2x-1)(2x+1)}{2x-1}$

$\displaystyle=\lim_{x\to1}(2x+1)$

$\displaystyle=(2(1)+1)$

$\displaystyle=2+1=3$