limit -> 2 xpower10 - 1024/x-2
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Hey





Or..
By L - Hospital :
( The limit has 0/0 form )
Differentiate the Numerator and Denominator to get :



Both ways ! you get your answer ^^"
Or..
By L - Hospital :
( The limit has 0/0 form )
Differentiate the Numerator and Denominator to get :
Both ways ! you get your answer ^^"
CvM1:
i think 2nd is easy way... thanks for guidence
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