limit of x tending to 0 e power x minus x minus one upon x
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according to ur question :
lim e^x - x - 1/x
x-> 0
= e^0 - 0 - 1/0 = 1 - 1/0 = -1/0
does not exist ❌
since + and negative limits are infinite
if u think ur question is wrong then:
lim (e^x - x - 1) / x
x -> 0
lim (e^x - 1)/ 1 ... by L hospital rule
x-> 0
= (e^0 - 1) = 1 - 1 = 0
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