Math, asked by sani807, 1 year ago

limit tends to 0 3u^2-2u/u

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Answered by GB2010
5
.Hiiii..

Answer is....
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Answered by Anonymous
8
Lim u →0 3u²-2u/u
Put u = 0
We get 0/0 form

Now :-
Lim u→0 u(3u-2)/u
=>
Lim u→0 3u-2
Put u =0
We get :
Lim u →0 3u²-2u/u = -2
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