limit tends to 1 root1+x-root1-xbyx
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silenteyeArun:
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first of all, limit tends to zero not one
By assuming it is 0, we use the special limit formula given by:-
Lim. f(x). =Lim. f'(x)
x->0. g(x). x->0 g'(x)
(We differentiate the numerator and denominator)
By that,
we get the equation equal to
1/(2* root(x+1)) - 1/(2* root(x-1))
The equation is not in 0/0 form anymore, we keep the limits which evaluates the answer equal to 0.
By assuming it is 0, we use the special limit formula given by:-
Lim. f(x). =Lim. f'(x)
x->0. g(x). x->0 g'(x)
(We differentiate the numerator and denominator)
By that,
we get the equation equal to
1/(2* root(x+1)) - 1/(2* root(x-1))
The equation is not in 0/0 form anymore, we keep the limits which evaluates the answer equal to 0.
Since I am not allowed to post it again, I will tell you here
Simple.
okk
plzz
multiply both numerator and denominator by root(x^2+1) + root (x^2-1)
multiply the both term of numerator
this will reduce numerator to a single term
please ask it again.....post another question i will tell you there
tq
i understand
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