limit tends to 2 (4/x^2-4)+(1/2-x)
Answers
Answered by
1
refer the page
))))))))))))))
Attachments:
![](https://hi-static.z-dn.net/files/dac/0c3ad0b090d44cf3efe237310ef5ecf7.jpg)
Answered by
1
Step-by-step explanation:
2(4/x^2-4)+(1/2-x)
8/2x^2-8+1/2-x
Similar questions