Limit x-0 (1-cos(6x))/x²
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Answered by
10
Hi Mate!!
Lt. 1 - cos ( 6x ) / x²
x--->0
Lt Sin ( 6x ) ×6 / 2x
x--->0
Lt Cos ( 6 x ) ×36 / 2
x--->0
= 18
Have a nice time.
Lt. 1 - cos ( 6x ) / x²
x--->0
Lt Sin ( 6x ) ×6 / 2x
x--->0
Lt Cos ( 6 x ) ×36 / 2
x--->0
= 18
Have a nice time.
Answered by
8
i hope your question right answer is
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