Question

limit x→0 1-cos x÷x
a)0 b)1 c)-1 d)5

Answer 1

Answer:

$a: 0$

Step-by-step explanation:

$\frac{1-cosx}{x} * \frac{1+cosx}{1+cosx}$

$\frac{1-cos^{2}x }{x(1+cosx)}$

$\frac{sin^{2}x }{x(1+cosx)}$

Putting the value of x+0

Since sin x=0

$sin^{2} x=0$

Hence the answer is zero.