Question

limit\x=0 sin5x\SIN15X​

Answer 1

Step-by-step explanation:

Use L' hospital theorem =

= 5cos5x/15 cos15x= 5/15 = 1/3

Thanks....❤

Answer 2

• Solution:-

$\tt lim_{x \to 0} \: \: \frac{ \sin(5x) }{15x} \\ \\ \tt \: lim_{x \to 0} \: \: \frac{ \frac{ \sin(5x) }{5x} \times 5}{ \frac{ \sin(15x) }{5x \times 3} \times 15} \\ \\ \tt \: lim_{x \to 0} \: \: \frac{ \frac{ \sin(5x) }{5x} \times 5 }{ \frac{ \sin(15x) }{15x} \times 15 } \\ \\ \tt \: = \: \: \frac{1 \times5 }{1 \times 15} \\ \\ \tt \: = \: \: \frac{5}{15} \\ \\ \tt \: = \: \: \frac{1}{3} is \: answer. \\ \\ \\ \\ \tt \bf \red { \odot \:Explanation} \\ \\ \tt \: lim_{x \to 0} \: \: \frac{ \sin( \theta) }{ \theta} = 1 \\ \\ \tt \: where \: \theta \: is \: in \: redian \: .$