limit x-27
x^1/3+3)(x^1/3-3)/x-27
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We have,
x→27limx−27(x1/3+3)(x1/3−3)
=x→27lim(x1/3−3)(x2/3+9+3x1/3)(x1/3+3)(x1/3−3) [cancle both (x1/3−3)]
=9+9+3×33+3
=276
=92
Hence the required answer is 92.
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