Question

limit
x~3.
$x {}^{2} + 3x + 2 \div x { }^{2} - 6x + 9$


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Answer 1

Refer the attached picture.

Answer 2

$\frac{ {x}^{2} + 3x + 2}{ {x}^{2} - 6x + 9 } \\ \\ \frac{ {x}^{2} + x + 2x + 2}{ {x}^{2} - 3x - 3x + 9} \\ \\ \frac{(x + 1)(x + 2)}{(x - 3)(x - 3)}$