Question

limit X approaches 0 3 under root oneplus x minus
one upon x

Answer 1

$lim _{x - > 0} {3 \sqrt{1 + x} } - \frac{1}{x} \\ = > lim _{x - > 0} = ( \frac{3x\sqrt{1 + x} - 1 }{x} ) \\ put \: x \: = 0 \\ we \: get ....\: \\ lim _{x - > 0} = \frac{3(0) \sqrt{1 + 0 } - 1}{0} = \frac{ - 1}{0} = \infty \\ hence \: lim _{x - > 0} {3 \sqrt{1 + x} } - \frac{1}{x} \: = \infty$