Question

Limit x approaches to infinity (3x+7)/(x²-2)

Answer 1

Answer:

$\tt 0$

Step-by-step explanation:

We

$\tt \[ \lim_{x\to\infty} \dfrac{(3x+7)}{(x^2-2)}\]$

By L'Hôpital's rule,

$\rm \tt \[ \lim_{x\to c} \dfrac{f(x)}{g(x)}\]= \[ \lim_{x\to c} \dfrac{\dfrac{d}{dx}f(x)}{\dfrac{d}{dx}g(x)}\]$

$\tt = \[ \lim_{x\to \infty} \dfrac{3}{2x}\]$

$= \tt \dfrac{3}{2}· \dfrac{1}{\[ \lim_{x\to \infty} x\]}$

$\tt = 0$