Math, asked by kamran8669, 8 months ago

Limit x extended to zero one minus cos2x divided by x*sin2x

Answers

Answered by 217him217
0

Answer:

limx->0 (1-cos2x) /xsinx

= limx->0 (2sin2x) /(xcosx+sinx)

=limx->0 (4cos2x) /(cosx-xsinx+cosx)

= (4cos0)/(cos0-0+cos0)

=4/2

=2

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