Limit x extended to zero one minus cos2x divided by x*sin2x
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Answer:
limx->0 (1-cos2x) /xsinx
= limx->0 (2sin2x) /(xcosx+sinx)
=limx->0 (4cos2x) /(cosx-xsinx+cosx)
= (4cos0)/(cos0-0+cos0)
=4/2
=2
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