Question

limit x->infinity 39x^2 7x/54x^2 19

Answer 1

$\lim_{x \to \infty} \frac{39x^2-7}{54x^2+19}$

Divide the numerator and denominator of the fraction by x²

$\lim_{x \to \infty} \frac{39 - \frac{7}{x^2} }{54 + \frac{19}{x^2} }$

Rewriting the limits  if x ---> ∞ then 1/x   --> 0  that means 1/x^2  ----> 0

On substitution 

We get

39/54