Limit x tending to 0 xsinx
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Answer:
as limit x tends to 0 x sinx
Explanation:
x sinx we can change these by multyping and dividing with x then eqn changes into limit x tends to 0 x^2 sinx /x so as limit x tends to 0 sinx/x =1 so remaining limit x tends to 0 x^2 answer is 0 .
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