limit x tends to 0 1 -cos2x/x^2
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1
Answer:
lim
1−x
−2/3
1−x
−1/3
Here putting the limit x→1 we
get
0
0
from (undefined form )
None we can apply L-Hospital Rule
⇒
x→1
lim
d(1−x
−2/3
)
d(1−x
1−/3
)
⇒
x→1
lim
0−(
3
−2
x
−2/3
−1)
0−(
3
−1
x
−1/3−1
)
{
dx
d
(x
n
)=nx
n−1
=d(x)
n
⇒
x→1
lim
+
3
2
x
−5/3
+
3
1
x
−4/3
⇒
x→1
lim
2
1
x
−4/3
+
3
5
⇒
x→1
lim
2
1
x
3
1
⇒
2
1
(1)
1/3
⇒
2
1
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