Limit x tends to 0 (1+x+x^2)-e^x/x^2
Attachments:
Answers
Answered by
1
it is in 0/0 form
therefore apply L-hospital rule
differentiate numerator and denominator separately two times
then we get ans 1/2
therefore apply L-hospital rule
differentiate numerator and denominator separately two times
then we get ans 1/2
Similar questions