Question

Limit x tends to 0 [( tanx - sinx )/x^3 = ?

Answer 1

Answer:

limx->0 (tanx-sinx) /x³

= limx->0 (sec²x-cosx) /3x²

= limx->0 (2sec²xtanx + sinx) /6x

= limx->0 (2(2sec²xtan²x + sec^4x) + cosx)/6

= ( 2(0+1)+1)/6

=3/6

=1/2