Question

limit x tends to 0 (x)^x^2​

Answer 1

Answer:

1

Step-by-step explanation:

y = x^(x^2)

log y = (x^2) log x

log y = 0 if x ~ 0

therefore y = e^0

i,e..y = 1

hence ...

(x)^x^2 =1 if x ~ 0