Question

limit x tends to 1 (x square-1)/(x-1)(x+3)​

Answer 1

Answer:

1/2

Step-by-step explanation:

$x^{2}$-1/(x-1)(x+3) = (x-1)(x+1)/(x-1)(x+3) = (x+1)/(x+3)

introducing limits, put x = 1 as limit x tends to 1

so ( (1) + 1 ) / ( (1) + 3 ) = 2/4 = 1/2

so the limit will tend to 1/2 when x tends to 1

hope it helps