Question

Limit x tends to π/2 4√2 sin3x +sinx

Answer 1

Answer:

answer= 1-4√2

Step-by-step explanation:

limit x->90 {4√2sin3x+sinx}.....(I)

since we know that

sin3x=3sinx-4sin³x

put it in the (I) equation

we get

limit x->90 {4√2[3sinx-4sin³x]+sinx}

now we know that

sin 90=1 and sin³90=1

so,

=>{4√2[3×1-4×1]+1}

=>{[4√2×(-1)]+1}

=>-4√2+1=>1-4√2 is answer