Math, asked by Kingtgreat, 3 months ago

limit x tends to -∞(2x-3)/√(x²-1)

Answers

Answered by singhadityaanita
4

Answer:

Explanation: limx→1x−1 x2−1. =limx→1x−1(x−1)(x+1). =limx→1x−1 x−1⋅limx→11x+1. =1⋅12.

12 Explanation: limx→1x−1x2−1 =limx→1x−1(x−1)(x+1) =limx→1x−1x−1⋅limx→11x+1 =1⋅12

Answered by dhruvighelani
2

Answer:

lim_(x to 1) (x-1)/(x^2-1)

=lim_(x to 1) (x-1)/((x-1)(x+1))

=lim_(x to 1) (x-1)/(x-1) *lim_(x to 1) 1/(x+1)

=1* 1/2

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