Question

limit x tends to 4 (3-√5+x/1-√5-x)​

Answer 1

Step-by-step explanation:

lim(x → 4) [3 - √(5 + x)]/[1 - √(5 - x)]

putting x = 4, we get form of limit 0/0.

so, we can apply L - Hospital rule,

differentiating numerator and denominator individually.

lim(x → 4) [0 - 1/2√(5 + x) × 1]/[0 - 1/2√(5 - x) × -1]

= lim(x → 4) [1/√(5 + x)]/[1/√(5 - x)]

= lim (x → 4) √(5 - x)/√(5 + x)

= √(5 - 4)/√(5 + 4)

= 1/3

Answer 2

Answer:

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