Question

limit x tends to 5 (e^x-e^5)/x-5​

Answer 1

Step-by-step explanation:

We have,

$= \lim_{x \rarr5} \frac{5( {e}^{x} - {e}^{5} )}{x - 5}$

$= \lim_{x \rarr5} \frac{5 {e}^{5} ( {e}^{x - 5} - 1)}{x - 5}$

$=5 {e}^{5} \lim_{(x - 5) \rarr0} \frac{ {e}^{x - 5} - 1 }{x - 5}$

$= 5 {e}^{5}$