Question

Limit x tends to 5 sqrt(x+4) -3 / sqrt(3x-11-2)

Answer 1

Step-by-step explanation:

limit x tends to 5 underroot ( x+4 ) -3 / under root ( 3 x -11-2

Answer 2

Here:

To find$\lim_{x \to \inft5} (\sqrt{x+4} -3 /\sqrt{3x-11-2})$

Solution:

$\lim_{x \to \inft5} (\sqrt{x+4} -3 /\sqrt{3x-11-2})$

$\lim_{x \to \inft5}\sqrt{x+4}}-3/\sqrt{3x-9-2-2}$

$\lim_{x \to \inft5} \sqrt{x+4} -3/\sqrt{3}(\sqrt{x-3} )-\sqrt{4}$

$\lim_{x \to \inft5}(\sqrt{x+4} -3)/\sqrt{3}(\sqrt{x-3})-2\ * \sqrt{3} (\sqrt{x-3} +2/\sqrt{3} (\sqrt{x-3} +2$

$\lim_{x \to \inft5}\sqrt{x+4} *\sqrt{3x-9} +2(\sqrt{x+4})-3(\sqrt{3x-9} )-6/3(x-3)-4$

$\lim_{x \to \inft5} 3\sqrt{6} +2\sqrt{9} -3\sqrt{6} -6/2$

$\lim_{x \to \inft5} 6-6/2$

$=0$

Therefore, $\lim_{x \to \inft5} (\sqrt{x+4}-3/\sqrt{3x-11-2} =0$.