Question

limit x tends to 5 x^2+3x-10 / x +5

Answer 1

$\lim_{x \to 5} \: \frac{ {x}^{2} + 3x - 10}{x + 5} \\ = \lim_{x \to 5} \: \frac{(x + 5)(x - 2)}{x + 5} \\ = \lim_{x \to 5} \: (x - 2) = 5 - 2 = 3$