limit x tends to infinity 2^x-1 tan (a/2x)
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Answered by
3
I cannot figure out how to solve this trigonometric limit:
limx→0(1x2−1tan2x)
I tried to obtain x2tan2x, cos2xsin2x and simplify, and so on. The problem is that I always go back to the indeterminate ∞−∞
Has someone a different approach to solve this limit?
Answered by
5
Answer:
Step-by-step explanation:
limx→0(1x2−1tan2x)
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