Question

limit x tends to zero [1-cosx]/x²

Answer 1

put x=0 we get 0/0. form
so apply L hospitals rule we get
sinx/2x but it will give again 0/0form when we put x=0 so apply L hospitals rule again we get
cosx/2.....now put x=o we get the answer =1/2

Answer 2

Hi Mate!!!

Put x = 0. we get 0/0 form. so, by using L hospitals rule which states that differentiate nr and dn separately till u come out from 0/0 form

Lt. Sin(x) / 2x
x-->0

Lt. Cos(x) /2
x--->0.



= 1/2



Have a great future ahead