Question

limit X tends to zero root x + 4 minus 2 upon root x + 9 - 3

Answer 1

heya your answer is here .... hope it helps

Answer 2

Answer:

3/2

Step-by-step explanation:

$\displaystyle\frac{\sqrt{x+4}-2}{\sqrt{x+9}-3}\\\\=\frac{(\sqrt{x+4}-2)(\sqrt{x+4}+2)(\sqrt{x+9}+3)}{(\sqrt{x+9}-3)(\sqrt{x+9}+3)(\sqrt{x+4}+2)}\\\\=\frac{((x+4)-4)(\sqrt{x+9}+3)}{((x+9)-9)(\sqrt{x+4}+2}\\\\=\frac{x(\sqrt{x+9}+3)}{x(\sqrt{x+4}+2)}\\\\=\frac{\sqrt{x+9}+3}{\sqrt{x+4}+2}\\\\\rightarrow\frac{\sqrt9+3}{\sqrt4+2}\ \text{as}\ x\rightarrow 0\\\\=\frac64\\\\=\frac32$