Question

limit X tends to zero tan8 x divided by tan 6x
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Answer 1

Step-by-step explanation:

$\sf \lim _{x -> 0} \frac {tan8x}{tan6x}$

$\sf Dividing\: both\: numerator \:and\:denominator \:by \:x$

$\sf \lim _{x -> 0} \frac {tan8x.x}{tan6x.x}$

$\sf \frac {8}{6}$

$\sf \frac {4}{3}$

THANKS!!!

Answer 2

$\frac{lim}{x = > 0} \frac{ \tan(8x) }{ \tan(6x) } \\ \frac{lim}{x = > 0} \frac{ \frac{ \tan(8x) \times 8 }{8} }{ \frac{ \tan(6x) \times 6 }{6} } \\ taking \: limit \\ = \frac{1 \times 8}{1 \times 6} \\ = \frac{8}{6}$

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