Question

limit X tends to zero tanax/tanbx​

Answer 1

Answer:

Stepvfbvrrfgtyhyjukikitun-by-step explanation:

Answer 2

Answer:

${ \huge{ \tt{ \red{ \lim _ {x \mapsto 0} \: \frac{\tan(ax)}{ \tan(bx) }}}}}$

$\huge{{ \mathcal{\huge {\green{answer }}}} \huge \pink\dashrightarrow \huge \red{ \frac{a}{b}}}$

Step-by-step explanation:

Move the term

${ \red{\huge{ \frac1B}}}$,outside of the limit because it is constant with respect to x.

{$\frac1B\lim_{x→0}tan(Ax)x$}

Apply L'Hospital's rule.

$\huge \pink{ \frac1B \lim _ {x→0}A{sec }^{2} (Ax)}$

Evaluate the limit.

$\huge \green{ \tt{ \frac{A}{B }{sec }^{2} (A \lim _{ x→0}x)}}$

Evaluate the limit of x by plugging in 0 for x.

$\huge \color{grey} \frac{A}{B}{ \sec }^{2} (A⋅0)$

Multiply A by 0.

$\huge{ \color{cyan}{\frac{A}{B}{ \sec }^{2} (0)}}$,The exact value of sec(0) is 1.

$\huge{ \therefore \frac ab \: \: \: \: is \: t he \: anser}$