limit X tends to zero to sin x minus sin 2x by x cube
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the answer should be zero
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write sin2x=2sinxcosx .. take sinx common.. it will give u limχ→0 sinx(1–2cosx)/x³ .. then {(1–2cosx} = -1 at x→0 } then limit becomes limx→0 (–sinx)/x³ which will give u (⁻∞ )as the ans.
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