Question

limit x tents to 1 (x^40-1)÷(x^20-1)​

Answer 1

Answer:

$\displaystyle{\implies 2}$

Step-by-step explanation:

Given :

$\displaystyle{ \lim_{x \to 1} \dfrac{x^{40}-1}{x^{20}-1}}\\\\\\\displaystyle{ \lim_{x \to 1} \dfrac{x^{20^2}-1^2}{x^{20}-1}}\\\\\\\displaystyle{ \lim_{x \to 1} \dfrac{(x^{20}+1)(x^{20}-1)}{(x^{20}-1)}}\\\\\\\displaystyle{ \lim_{x \to 1} x^{20}+1}$

Putting x = 1 now :

$\displaystyle{\implies 1^{20}+1}\\\\\displaystyle{\implies 1+1}\\\\\displaystyle{\implies 2}$