Chemistry, asked by nadiira1606, 11 months ago

Limiting molar conductivity of NH₄OH
(i.e.,∧°ₘ(NH₄OH) is equal to :
(a) ∧°ₘ (NH₄OH) + ∧°ₘ (NaCl) - ∧°m(NaOH)
(b) ∧°m(NaOH) + ∧°ₘ (NaCl) + ∧°ₘ (NH₄Cl)
(c) ∧°ₘ (NH₄OH) + ∧°ₘ (NH₄Cl) - ∧°ₘ (HCl)
(d) ∧°ₘ (NH₄Cl) + ∧°m(NaOH - ∧°ₘ (NaCl))

Answers

Answered by Anonymous

1

$\huge{\bold{\red{\star{\pink{Heya !}}}}}$

Option [D] is the answer ✔️

Previous Question

Next Question

Similar questions

Social Sciences, 5 months ago

Hii friends please answer my 4 questions ...

World Languages, 5 months ago

i want to labble this bell diagram...

Math, 5 months ago

solve acosx+bcosx=C where c=≤√a²+b²...

Chemistry, 11 months ago

The electrode potentials for Cu²⁺(aq) + e⁻ → Cu⁺(aq) and Cu⁺(aq) + e⁻ → Cu(s) are + 0.15 V and + 0.50, respectively. The value of E°Cu²⁺ /Cu will be : (a) 0.500 V (b) 0.325 V (c) 0.650 V (d) 0.150 V...

Chemistry, 11 months ago

An increase in equivalent conductance of a strong electrolyte with dilution is mainly due to: (a) increase in ionic mobility of ions (b) 100% ionisation of electrolyte at normal dilution (c) increase in both i.e. number of ions and ionic mobility of ions (d) increase in number of ions...

Chemistry, 1 year ago

The second ionization enthalpy $IE_{2}$ of the elements of the second period are given below: Element: Li Be B C N O F Ne $IE_{2}$ (kJ/mol): 7294 1756 2430 2354 2856 3396 3377 3966 Explain: (a) Why is $IE_{2}$ of Li so much higher than for all other elements of this period? (b) What is the general trend from Be to Ne of increasing $IE_{2}$ ? (c) Why...

Chemistry, 1 year ago

The size of isoelectronic species - $F^{-}$ , Ne and $Na^{+}$ is affected by: (a) nuclear charge (Z) (b) valence principal quantum number (n) (c) electron–electron interaction in the outer orbitals (d) none of the factors because their size is the same...

Chemistry, 1 year ago

The solubility product constants of $Ag_{2}CrO_{4}$ and AgBr are 1.1 × $10^{-12}$ and 5.0 × $10^{-13}$ respectively. Calculate the ratio of the molarities of their saturated solutions.