Chemistry, asked by vijaynegisoala4762, 1 year ago

Limiting molar conductivity of NH₄OH (i.e., \bigg \lgroup \Lambda^o_{m(NH_4OH)}\bigg \rgroup ) is equal to :
(a) \Lambda^o_{m(NH_4Cl)} + \Lambda^o_{m(NaCl)} - \Lambda^o_{m(NaOH)}
(b) \Lambda^o_{m(NaOH)} + \Lambda^o_{m(NaCl)} - \Lambda^o_{m(NH_4Cl)}
(c) \Lambda^o_{m(NH_4OH)} + \Lambda^o_{m(NH_4Cl)} - \Lambda^o_{m(HCl)}
(d) \Lambda^o_{m(NH_4Cl)} + \Lambda^o_{m(NaOH)} - \Lambda^o_{m(NaCl)}

Answers

Answered by varun200516
0

option c is the correct answer for the question

Answered by Anonymous
0
 \huge {\boxed{ \boxed{ \boxed {\mathfrak{ \blue{Answer ;}}}}}}

 <b>
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 \mathbb{NICE...QUESTION}

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→ [B]


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