Math, asked by sss1585377, 1 month ago

limiting reagent। ( 1.23, 1.24)​

Answers

Answered by ayesharahaman749
1

Answer:

C6H12O6, the oxygen is in excess and glucose is the limiting reactant. If less than 6 moles of oxygen are available per mole of glucose, oxygen is the limiting reactant. The ratio is 6 mole oxygen per 1 mole glucose, OR 1 mole oxygen per 1/6 mole glucose.15-Aug-2020

Similar questions