Question

LIMITS
1 1
(1 + x)" -(1-x)"
Lim
11
1
1
x →
(1 + x)" -(1-x)"​

Answer 1

Answer:

......................

Answer 2

Step-by-step explanation:

x→1

lim

1−x

−2/3

1−x

−1/3

Here putting the limit x→1 we

get

0

0

from (undefined form )

None we can apply L-Hospital Rule

⇒

x→1

lim

d(1−x

−2/3

)

d(1−x

1−/3

)

⇒

x→1

lim

0−(

3

−2

x

−2/3

−1)

0−(

3

−1

x

−1/3−1

)

{

dx

d

(x

n

)=nx

n−1

=d(x)

n

⇒

x→1

lim

+

3

2

x

−5/3

+

3

1

x

−4/3

⇒

x→1

lim

2

1

x

−4/3

+

3

5

⇒

x→1

lim

2

1

x

3

1

⇒

2

1

(1)

1/3

⇒

2

1

solution