Question

limits #find value of k if limit exists at x= 0

Answer 1

1 - cos4x = 2 sin^2 2x

(1-cos4x)/8x.x= 2 sin^2 2x/ 8x.x
= 2 sin^2 2x/ 4 x.x.2
AS SIN^2 2X/ 4 X.X = 1 WHEN LIMIT X TENDS TOzero
= 1

Answer 2

Hope this will help u... :-)