limx-0 1-cos 5x/1-cos 10x
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Answer:
-cos(5X)-cos(10x)+(lm(x)-1
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Given limit
=
x→0
lim
2sin
2
3x
2sin
2
2x
=
x→0
lim
sin
2
3x
sin
2
2x
=
x→0
lim
(
3x
sin3x
)
2
×9x
2
(
2x
sin2x
)
2
×4x
2
=
9
4
.
3x→0
lim
(
3x
sin3x
)
2
2x→0
lim
(
2x
sin2x
)
2
=(
9
4
×
1
1
)=
9
4
.
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