Question

limx-0 sin
log(1+x3)​

Answer 1

Answer:

1

Step-by-step explanation:

$\lim_{x \to 0} \frac{log(1+x^3)}{sin^3x}$

=$\lim_{x \to 0} \frac{log(1+x^3)}{x^3} \lim_{x \to 0} \frac{x^3}{sin^3x}$

= 1 × $(\lim_{x \to 0} \frac{x}{sinx})^3$

= 1 × 1 ³= 1