Question

limx→0x2Sin(x)–ex2Cos(x+π/2) is

Answer 1

Given:

limx→0x2Sin(x)–ex2Cos(x+π/2) is

To find:

limx→0x2Sin(x)–ex2Cos(x+π/2) is

Solution:

From given, we have the data as follows.

lim (x → 0) x² sin (x) - e x² cos (x + π/2)

Substitute the value of x in the above equation, as per the given limit value. So, we get,

= 0² sin (0) - e (0)² cos (0 + π/2)

= 0 - 0

= 0

∴ lim (x → 0) x² sin (x) - e x² cos (x + π/2) = 0

Therefore, the value of the limit of the given function is zero.