limx→1 sin|||x|-2|-3|
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Answer would be Sin 2
Simply just put x=1+ or 1-
The answer will gonna come out to be sin2 as |x| only gets + or - sign if x is around 0;
Hope it will help...
Simply just put x=1+ or 1-
The answer will gonna come out to be sin2 as |x| only gets + or - sign if x is around 0;
Hope it will help...
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