limx→∞ e^x/x². solve using L- Hospital rule
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Consider r>0; then
limx→∞xrex=0
Indeed, you can start from x<ex (for x>0), so x2<ex/2 and therefore
0<xex<2ex/2
and the squeeze theorem allows to conclude. Of course also l’Hôpital works:
limx→∞xex=limx→∞1ex
For the general limit, write it as
limx→∞(xex/r)r=limx→∞rr(x/rex/r)r=0
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