limx→√π sin(x²)-cos(3x²/2)/cos(x²/2)-sin(2x²)cos²(x²)
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limx→√π sin(x²)-cos(3x²/2)/cos(x²/2)-sin(2x²)cos²(x²) =1
Step-by-step explanation
- Step 01:- find inderminant form step02:- change lim value put x² = t step03:- use L-Hospital rule
Then , we will get required Answer
Solution is refered to the attachment .
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refer to this attachment ✅✅
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