Question

Limx→tends to π/3 sec²x-8/
tan²x-3

Answer 1

Step-by-step explanation:

Limx→tends to π/3 sec²x-8/

tan²x-3

Lim. sec^2x -8

x=0 --------------

tan^2x-3

Lim. 1+ tan^2x - 8

x=0. -----------------

tan^2x - 3

Lim. tan^2x - 7

x=0. --------------

tan^2x -3

applying limit x=0

0 -7. 7

-----. = -----

0 -3. 3